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4-36y^2=0
a = -36; b = 0; c = +4;
Δ = b2-4ac
Δ = 02-4·(-36)·4
Δ = 576
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{576}=24$$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-24}{2*-36}=\frac{-24}{-72} =1/3 $$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+24}{2*-36}=\frac{24}{-72} =-1/3 $
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